1. Find the Derivative - d/dx sin(xy) - Mathway
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2. What is the derivative of the function y=sin(xy)? - Socratic
17 okt 2016 · dydx=ycos(xy)1−xcos(xy). Explanation: Using implicit differentiation, the product rule, and the chain rule, we get. ddxy=ddxsin(xy).
dy/dx = (ycos(xy))/(1-xcos(xy)) Using implicit differentiation, the product rule, and the chain rule, we get d/dxy = d/dxsin(xy) => dy/dx = cos(xy)(d/dx(xy)) =cos(xy)[x(d/dxy)+y(d/dxx)] =cos(xy)(xdy/dx + y) =xcos(xy)dy/dx + ycos(xy) => dy/dx - xcos(xy)dy/dx = ycos(xy) => dy/dx(1-xcos(xy)) = ycos(xy) :. dy/dx = (ycos(xy))/(1-xcos(xy))
3. How do you find the derivative of y = sin(x+y)? - Socratic
28 jul 2016 · dydx=cos(x+y)1−cos(x+y). Explanation: You simply differentiate both sides with respect to x . The left side would simply give you dydx .
dy/dx= cos(x+y)/{1-cos(x+y)} You simply differentiate both sides with respect to x. The left side would simply give you dy/dx. For the right side, however, you must make use of the chain rule for derivatives of composite functions (functions of functions). Thus d/dx (sin(x+y)) = cos(x+y) xx d/dx (x+y) = cos(x+y) (1+dy/dx) Thus, we get dy/dx = cos(x+y) (1+dy/dx) We can easily solve this for the quantity dy/dx: (1-(cos(x+y)) dy/dx = cos(x+y) implies dy/dx= cos(x+y)/{1-cos(x+y)}
4. derivative of y=sin(xy) - Symbolab
Frequently Asked Questions (FAQ). What is the derivative of y=sin(xy) ? The derivative of y=sin(xy) is cos(xy)y. What is the first derivative of y=sin(xy) ?
Detailed step by step solution for derivative of y=sin(xy)
5. How do you differentiate y = sin(xy)?
9 jan 2020 · Verify that y = A cos x + sin x satisfies the differential equation cos x d y d x + sin x y = 1.
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6. Calculus Examples - Find dy/dx y=sin(xy) - Mathway
The derivative of y y with respect to x x is y' y ′ . y' ...
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7. How to Find dy/dx by Implicit Differentiation Given a ... - Sciencing
30 jan 2020 · To determine the derivative of y = sin(xy), we will use implicit differentiation by remembering that (d/dx)y = y'.
You can find the derivative of sin(xy) using implicit differentiation. This method of differentiation is helpful for situations in which you have more than one variable that you can differentiate. For an expression like sin(xy), you can differentiate with respect to x or y in calculus.
8. If sin(xy)+xy=x2−y, then find dydx
sinxy+xy=x2−y. ⇒ddx(sinxy)+ddx(xy)=ddx(x2−y). ⇒cosxy(y+xdydx)+y−xdydxy2=2x−dydx. ⇒ycosxy+xcosxydydx+1y−xy2dydx=2x−dydx. ⇒dydx(1+xcosxy−xy2)=2x−ycosxy−1y. dydx=2 ...
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9. Find the first partial derivatives of the function. z = x sin(xy)? - Cuemath
The first partial derivatives of the function. z = x sin(xy) are sin(xy) + xy cos(xy) and x^2cos(xy).
The first partial derivatives of the function. z = x sin(xy) are sin(xy) + xy cos(xy) and x^2cos(xy).
